Question:medium

Identify the substrate ' A ' in the following conversion.
A $\xrightarrow[\text{H}_3\text{O}^+]{\text{AlH}(i-\text{Bu})_2}$ Pent-3-enal}

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$\text{DIBAL-H}$ + Nitrile $\to$ Aldehyde. It does not reduce the $\text{C}=\text{C}$ double bond.
Updated On: May 7, 2026
  • Pentanenitrile
  • Pent-3-enenitrile
  • Pent-3-en-1-amine
  • Pent-3-ynenitrile
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
DIBAL-H (\(\text{AlH}(i\text{-Bu})_2\)) is a selective reducing agent that can reduce nitriles (\(-\text{CN}\)) to aldehydes (\(-\text{CHO}\)) at low temperatures without affecting carbon-carbon double bonds.
Step 2: Key Formula or Approach:
\[ \text{R-CN} \xrightarrow{\text{DIBAL-H, then } \text{H}_3\text{O}^+} \text{R-CHO} \] Step 3: Detailed Explanation:
The product is Pent-3-enal, which is an unsaturated aldehyde: \(\text{CH}_3\text{-CH=CH-CH}_2\text{-CHO}\).
Since the reagent converts a nitrile to an aldehyde, the starting material 'A' must be a nitrile with the same carbon skeleton and double bond position.
The corresponding nitrile is Pent-3-enenitrile (\(\text{CH}_3\text{-CH=CH-CH}_2\text{-CN}\)).
Step 4: Final Answer:
The substrate 'A' is Pent-3-enenitrile.
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