Step 1: Use the formula
Steric number $=\frac{1}{2}(7+5)=6$. So iodine is $sp^3d^2$ hybridised.
Step 2: Place the lone pair
Out of $6$ octahedral positions, one holds the lone pair. The $5$ F atoms form a square base with iodine slightly above it, giving a square pyramid.
Final Answer:
Option (D), square pyramidal.
\[ \boxed{\text{(D)}} \]
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