Step 1: Understanding the Question:
The reaction involves the reduction of a nitro group (\( -NO_2 \)) to an amino group (\( -NH_2 \)) using metal in acid. Step 2: Detailed Explanation:
1. Nitroethane is \( CH_3CH_2NO_2 \).
2. \( Sn/HCl \) is a reducing agent that converts the nitro group into a primary amine group.
3. The reaction is:
\[ CH_3CH_2NO_2 + 6[H] \xrightarrow{Sn/HCl} CH_3CH_2NH_2 + 2H_2O \]
4. The product \( CH_3CH_2NH_2 \) is named ethanamine (Ethylamine). Step 4: Final Answer:
The product is Ethanamine.