Question

A car passes three points A, B and C at \(3\) m/s, \(6\) m/s and \(9\) m/s respectively in a straight line with uniform acceleration. If distance \(AB = 60\) m then find the distance BC.

• A. \(100\) m
• B. \(75\) m
• C. \(200\) m
• D. \(125\) m

Hint:

Use $v^2-u^2=2as$ on each stretch and divide.

Answer 1

The Correct Option is A

Step 1: Divide the two equations
$\frac{BC}{AB}=\frac{v_C^2-v_B^2}{v_B^2-v_A^2}=\frac{81-36}{36-9}=\frac{45}{27}=\frac53$.
$BC=\frac53\times60=100$ m. Option (A).

Final Answer:
Option (A). \[ \boxed{\text{(A)}} \]