The given sequence involves a series of reactions starting with benzene and propyl chloride in the presence of anhydrous AlCl3, followed by reactions with O2 and acid work-up to form compounds Q and R. Let's analyze each step:
-
First Reaction: The first step is a Friedel-Crafts alkylation. Propyl chloride (CH3CH2CH2Cl) reacts with benzene in the presence of anhydrous AlCl3 to form isopropylbenzene (cumene) due to rearrangement of the propyl carbocation.
-
Oxidation: Cumene is oxidized using O2 to form cumene hydroperoxide.
-
Acid Work-up: In the presence of an acid (H3O+/Δ), cumene hydroperoxide rearranges to form phenol and acetone.
Therefore, the products Q and R are phenol (Q) and acetone (R).
Thus, the correct answer is the structure shown in Option D.