Step 1: Start from the alcohol. The starting material is propan-1-ol, $CH_3CH_2CH_2OH$, a straight chain three carbon alcohol. Step 2: Convert alcohol to alkyl chloride. Treatment with HCl in the presence of $ZnCl_2$ (Lucas reagent) replaces the $-OH$ with $-Cl$, giving 1-chloropropane, $CH_3CH_2CH_2Cl$. Step 3: Swap chloride for iodide. Heating with NaI in dry acetone is the Finkelstein reaction, which exchanges chlorine for iodine to form 1-iodopropane, $CH_3CH_2CH_2I$. Step 4: Apply the Wurtz reaction. With sodium metal in dry ether, two molecules of the alkyl iodide couple together (Wurtz reaction): \[ 2\,CH_3CH_2CH_2I + 2Na \rightarrow CH_3CH_2CH_2CH_2CH_2CH_3 + 2NaI \] Step 5: Count the carbons in the product. Two propyl groups join to give a straight chain of six carbons, which is hexane. Step 6: Conclude. The major product is hexane, which is the answer marked as option 4. \[ \boxed{\text{Hexane}} \]
