Question:medium

Identify, from the following, the diamagnetic, tetrahedral complex:

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Tetrahedral complexes generally form with weak field ligands. However, CO is a strong field ligand that follows sp$^3$ hybridization due to back bonding effects.
Updated On: Nov 26, 2025
  • [Ni(Cl)₄]²⁻
  • [Co(C₂O₄)₃]³⁻
  • [Ni(CN)₄]²⁻
  • [Ni(CO)₄]
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The Correct Option is D

Solution and Explanation

Step 1: Determine Electronic Configuration
Nickel (Ni) has atomic number 28. Its electronic configuration is: \[ [Ar] 3d^8 4s^2 \]. Determine the oxidation state of Ni in the given complexes. 
Step 2: Analyze Each Complex 
(A) [Ni(Cl)$_4$]$^{2-}$ 
Chloride (Cl$^-$) is a weak field ligand.
The geometry is tetrahedral, involving sp$^3$ hybridization. 
This complex is paramagnetic due to unpaired electrons. It is not the correct answer. 
(B) [Co(C$_2$O$_4$)$_3$]$^{3-}$ 
Cobalt (Co$^{3+}$) is complexed with a strong field ligand (oxalate). 
The structure is octahedral, not tetrahedral. This is an incorrect choice. 
(C) [Ni(CN)$_4$]$^{2-}$ 
Cyanide (CN$^-$) is a strong field ligand. 
This complex exhibits dsp$^2$ hybridization, resulting in a square planar geometry. 
It is diamagnetic but not tetrahedral. This is an incorrect choice. 
(D) [Ni(CO)$_4$] 
Carbon monoxide (CO) is a strong field ligand. 
It induces electron pairing and sp$^3$ hybridization, forming a tetrahedral structure. 
The absence of unpaired electrons makes it diamagnetic. This is the correct answer. 
Final Answer: The complex that is both diamagnetic and tetrahedral is [Ni(CO)$_4$].

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