Step 1: Adsorption indicator idea:
The indicator does not react in solution. It is adsorbed by the precipitate once the precipitate carries a positive charge.
Step 2: Sequence:
Start: solution has free fluorescein, pale yellow. Excess $\text{Ag}^+$ at the end point charges the AgCl surface positively, which attracts the fluorescein anion. The surface becomes pink. Answer: pale yellow to reddish pink (C).
Final Answer:
Pale yellow to reddish pink.
\[ \boxed{\text{(C)}} \]