



The problem is asking which graphs represent Freundlich adsorption isotherms. To solve this, we need to understand the Freundlich adsorption isotherm equation.
The Freundlich adsorption isotherm is represented by the equation:
\[\frac{x}{m} = k \cdot p^{1/n}\]where:
In a log-log graph, the Freundlich isotherm can be written as:
\[\log \left( \frac{x}{m} \right) = \log k + \frac{1}{n} \log p\]This shows a linear relationship between \log \left( \frac{x}{m} \right) and \log p, indicative of a straight line with slope \frac{1}{n}.
Let's analyze each graph:
Graph A: This shows \frac{x}{m} vs p, which can represent the Freundlich isotherm.
Graph B: This shows \log \left( \frac{x}{m} \right) vs \log p, which fits perfectly with the linear form of Freundlich isotherm.
Graph C: This shows \frac{x}{m} vs c (concentration), not directly related to the Freundlich equation.
Graph D: This illustrates \frac{x}{m} vs p^{1/n}, which is another way to show the Freundlich isotherm.
Thus, the correct graphs that represent the Freundlich adsorption isotherms are:
Therefore, the correct answer is: A, B, D only.
In figure, a straight line is given for Freundrich Adsorption\((y=3 x+2505)\) The value of \(\frac{1}{ n }\)and\(\log K\)are respectively