Step 1: Understanding the Concept:
When an aryl halide (like Chlorobenzene) reacts with Sodium in dry ether, it undergoes the Fittig Reaction.
Step 2: Formula Application:
$2C_6H_5Cl + 2Na \xrightarrow{\text{dry ether}} C_6H_5-C_6H_5 + 2NaCl$.
Step 3: Explanation:
Two phenyl groups ($C_6H_5$) couple together to form a diphenyl (also called biphenyl) molecule.
Step 4: Final Answer:
The product 'A' is Biphenyl.