Question:medium

Ice of mass \(80\,\mathrm{g}\) at a temperature of \(-10^\circ\mathrm{C}\) is mixed with water of mass \(100\,\mathrm{g}\) at a temperature of \(20^\circ\mathrm{C}\).

The ratio of the masses of ice and water in the mixture at equilibrium is 

Given:

  • Latent heat of fusion of ice \(= 80\,\mathrm{cal\,g^{-1}}\)
  • Specific heat capacity of water \(= 1\mathrm{cal\,g^{-1}^\circ C^{-1}}\)
  • Specific heat capacity of ice \(= 0.5\mathrm{cal\,g^{-1}^\circ C^{-1}}\)

Show Hint

When ice and water are mixed, \[ \boxed{ \text{Heat lost} = \text{Heat gained}. } \] Always account for: \[ \boxed{ \begin{aligned} &\text{Heating of ice}, &\text{Melting of ice}, &\text{Heating of melted water (if any).} \end{aligned} } \]
Updated On: Jul 21, 2026
  • \(4:5\)
  • \(1:2\)
  • \(2:3\)
  • \(3:4\)
Show Solution

The Correct Option is B

Solution and Explanation

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