A slightly faster way avoids introducing the scheduled time T explicitly by working directly with the total time gap between the two walking speeds.
This confirms the distance is 5 km, matching option B, without needing to solve for the scheduled time T separately.
A flight, traveling to a destination 11,200 kms away, was supposed to take off at 6:30 AM. Due to bad weather, the departure of the flight got delayed by three hours. The pilot increased the average speed of the airplane by 100 km/hr from the initially planned average speed, to reduce the overall delay to one hour.
Had the pilot increased the average speed by 350 km/hr from the initially planned average speed, when would have the flight reached its destination?