Question:medium

How many moles of platinum will be deposited on the cathode when 0.40 F of electricity is passed through a 1.0 M solution of \(Pt^{4+}\)?

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For electrodeposition: \[ \text{Moles deposited}=\frac{\text{Faradays passed}}{\text{charge on ion}} \]
Updated On: Apr 29, 2026
  • 0.60 mol
  • 1.0 mol
  • 0.40 mol
  • 0.45 mol
  • 0.10 mol
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The Correct Option is

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