The total count of 3-digit integers is derived as:
\(= 999 - 100 + 1 = 900\)
Let \(N\) represent the count of 3-digit integers with unique digits.
Digits are selected from the set {0, 1, 2, ..., 9}, comprising 10 distinct digits.
For a 3-digit number, the following constraints apply:
Consequently, the count of 3-digit integers where all digits are distinct is:
\(N = 9 \times 9 \times 8 = 648\)
Therefore, the count of 3-digit integers with at least one repeated digit is calculated as:
\(= 900 - 648 = 252\)
Final Answer: \(\boxed{252}\)