Question

How does the maximum kinetic energy of photoelectrons relate to wavelength (\(\lambda\))?

• A. \(K.E \propto \lambda\)
• B. \(K.E \propto \lambda^2\)
• C. \(K.E \propto \frac{1}{\lambda}\)
• D. \(K.E \propto \sqrt{\lambda}\)

Hint:

Shorter wavelength light has higher photon energy, therefore it produces photoelectrons with greater kinetic energy. Hence \(K.E \propto \frac{1}{\lambda}\).

Answer 1

The Correct Option is C