Question:medium

Heterocyclic ring present in acetazolamide is

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Acetazolamide = Thia (Sulfur) + Dia (Two Nitrogens) + Azole (Ring).
Updated On: May 19, 2026
  • Thiophene
  • Thiazole
  • Thiadiazole
  • Oxathiazole
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The Correct Option is C

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