Question:medium
Heat is given to an ideal gas in an isothermal process. Then
Heat is given to an ideal gas in an isothermal process. Then
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In an isothermal process, the internal energy of an ideal gas does not change because temperature is constant, even though heat is added or work is done by the gas.
Updated On: Jun 30, 2026
- internal energy of the gas will decrease.
- internal energy of the gas will increase.
- internal energy of the gas will not change.
- the gas will do negative work.
Show Solution
The Correct Option is C
Solution and Explanation
Step 1: Understanding the Question:
In an isothermal process, the temperature of the ideal gas is kept constant. We need to evaluate the effect on internal energy based on thermodynamics laws.
Step 2: Detailed Explanation:
Internal energy (\( U \)) of an ideal gas depends solely on its absolute temperature (\( T \)).
The definition of an isothermal process is \( \Delta T = 0 \).
Therefore, \( \Delta U = n C_v \Delta T = 0 \).
Statement (C) "internal energy of the gas will not change" is correct.
Looking at the choice mapping, (C) corresponds to Option (B).
Step 4: Final Answer:
The correct choice is Option (B).
In an isothermal process, the temperature of the ideal gas is kept constant. We need to evaluate the effect on internal energy based on thermodynamics laws.
Step 2: Detailed Explanation:
Internal energy (\( U \)) of an ideal gas depends solely on its absolute temperature (\( T \)).
The definition of an isothermal process is \( \Delta T = 0 \).
Therefore, \( \Delta U = n C_v \Delta T = 0 \).
Statement (C) "internal energy of the gas will not change" is correct.
Looking at the choice mapping, (C) corresponds to Option (B).
Step 4: Final Answer:
The correct choice is Option (B).
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