Question

Heat energy absorbed by a system in going through the cyclic process shown in the figure is

• A. \(10^{7}\pi\,\text{J}\)
• B. \(10^{4}\pi\,\text{J}\)
• C. \(10^{2}\pi\,\text{J}\)
• D. \(10^{-3}\pi\,\text{J}\) \bigskip

Hint:

For any cyclic process, \[ \Delta U=0 \] and therefore \[ Q=W. \] The net heat absorbed equals the area enclosed by the loop on the \(PV\)-diagram.

Answer 1

The Correct Option is C

Concept: Cyclic process: \(Q = W =\) area enclosed. Circle in PV diagram: radius in P = 10 kPa, radius in V = 10 L. Area = \(\pi \times 10 \times 10 = 100\pi\) kPa·L = \(100\pi\) J = \(10^2\pi\) J.

Step 1: Write the final answer. \(\boxed{10^2\pi\,\text{J}}\)