Question:medium

Half-life period of a radioactive substance is \(10\,\text{min}\). Then amount of substance decayed in \(40\,\text{min}\) will be:

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After \(n\) half-lives: remaining \(=\left(\frac{1}{2}\right)^n\), decayed \(=1-\left(\frac{1}{2}\right)^n\).
Updated On: Apr 16, 2026
  • \(25\%\)
  • \(50\%\)
  • \(75\%\)
  • None of these
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The Correct Option is D

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