Given below are two statements :
Statement I : Compound (X), shown below, dissolves in \( NaHCO_3 \) solution and has two chiral carbon atoms.
Statement II : Compound (Y), shown below, has two carbons with \( sp^3 \) hybridization, one carbon with \( sp^2 \) and one carbon with \( sp \) hybridization.
In the light of the above statements, choose the correct answer from the options given below :
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An alkyne (\( -C \equiv C- \)) always contains \textbf{two} \( sp \) hybridized carbons. An allene (\( C=C=C \)) contains \textbf{one} \( sp \) hybridized carbon (the middle one).
To solve this problem, we will analyze each statement individually.
Statement I: Compound (X), shown below, dissolves in \(NaHCO_3\) solution and has two chiral carbon atoms.
Compound (X) contains a carboxylic acid functional group. Organic acids, such as carboxylic acids, can react with \(NaHCO_3\) to form a water-soluble salt, releasing carbon dioxide gas. Additionally, examining the structure of compound (X), it does have two chiral centers as indicated by the asymmetric carbon atoms (one on the cyclopentane ring and the other near the bromine substitution).
Thus, Statement I is true.
Statement II: Compound (Y), shown below, has two carbons with \(sp^3\) hybridization, one carbon with \(sp^2\) and one carbon with \(sp\) hybridization.
The structure of compound (Y) shows an alkyne group (triple bond), which means there exists a carbon with \(sp\) hybridization, and the surrounding carbon of the carbonyl (C=O) group is \(sp^2\) hybridized. But for the given structure of compound (Y), there is only one carbon next to the \(sp\) hybridized carbon, indicating that there aren't two \(sp^3\) hybridized carbons.
Thus, Statement II is false.
Based on the analysis, the correct answer is: Statement I is true but Statement II is false.
