At resonance, current in (B) is less than that in (A)
The r.m.s. current in (B) can be larger than that in (A)
The r.m.s. current in (A) is always equal to that in (B)
The r.m.s. current in (B) can never be larger than that in (A)
Show Solution
The Correct Option isD
Solution and Explanation
Step 1: Approach
Compare through the power or the impedance triangle.
Step 2: Idea
The resistor is the same in both. In B the reactances add a perpendicular component to the impedance, which can only make the magnitude larger: $Z_B\ge R=Z_A$.
Step 3: Consequence
With the same voltage, $I_B=V/Z_B\le V/Z_A=I_A$. The two are equal only when $X_L=X_C$ (resonance), which does not hold at 50 Hz here since $X_C$ is about 7960 ohm and $X_L$ is about 12.6 ohm.
Step 4: Answer
Option (D).
Final Answer:
The impedance of B is never smaller than 30 ohm, so its current never exceeds the 7 A in A, option (D).
\[ \boxed{\text{(D)}} \]