Question:medium

From Kepler's third law, the square of the period of revolution ($T$) is proportional to the cube of the semi-major axis ($R$). If a planet has $T_{p = 27T_{e}$, then:

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$R \propto T^{2/3}$. If time increases by a factor of 27, radius increases by $27^{2/3} = 9$.
Updated On: Apr 8, 2026
  • $R_{p} = 3R_{e}$
  • $R_{p} = 9R_{e}$
  • $R_{p} = 27R_{e}$
  • $R_{p} = R_{e}$
Show Solution

The Correct Option is B

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