Question:medium

\(\frac{\cos\theta}{1-\tan\theta} + \frac{\sin\theta}{1-\cot\theta}\) is equal to

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Convert tan and cot into sin and cos to simplify expressions easily.
Updated On: Apr 18, 2026
  • \(\sec\theta + \csc\theta\)
  • \(\sin\theta + \cos\theta\)
  • \(\tan\theta + \cot\theta\)
  • \(\sin\theta - \cos\theta\)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
To simplify trigonometric fractions, it is often best to convert all ratios into their basic forms, \(\sin \theta\) and \(\cos \theta\).
Step 2: Detailed Explanation:
The given expression is: \[ E = \frac{\cos \theta}{1 - \tan \theta} + \frac{\sin \theta}{1 - \cot \theta} \] Convert \(\tan \theta\) and \(\cot \theta\): \[ E = \frac{\cos \theta}{1 - \frac{\sin \theta}{\cos \theta}} + \frac{\sin \theta}{1 - \frac{\cos \theta}{\sin \theta}} \] Take LCM in the denominators: \[ E = \frac{\cos \theta}{\frac{\cos \theta - \sin \theta}{\cos \theta}} + \frac{\sin \theta}{\frac{\sin \theta - \cos \theta}{\sin \theta}} \] Invert and multiply: \[ E = \frac{\cos^2 \theta}{\cos \theta - \sin \theta} + \frac{\sin^2 \theta}{\sin \theta - \cos \theta} \] To make the denominators common, multiply the second term by -1: \[ E = \frac{\cos^2 \theta}{\cos \theta - \sin \theta} - \frac{\sin^2 \theta}{\cos \theta - \sin \theta} \] \[ E = \frac{\cos^2 \theta - \sin^2 \theta}{\cos \theta - \sin \theta} \] Using identity \( a^2 - b^2 = (a-b)(a+b) \): \[ E = \frac{(\cos \theta - \sin \theta)(\cos \theta + \sin \theta)}{\cos \theta - \sin \theta} \] \[ E = \cos \theta + \sin \theta \].
Step 3: Final Answer:
The simplified expression is \( \sin \theta + \cos \theta \).
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