Question:medium

$ (\frac{1+i}{1-i})^{228}$

Show Hint

Memorize the standard simplifications: $\frac{1+i}{1-i} = i$ and $\frac{1-i}{1+i} = -i$. These frequently appear in complex number problems and save significant calculation time.

Updated On: Mar 30, 2026

$ -4(\frac{1-i}{1+i})^{226} $
$ 4(\frac{1-i}{1+i})^{226} $
$ (\frac{1-i}{1+i})^{228} $
$ -(\frac{1-i}{1+i})^{228} $

Show Solution

The Correct Option is C

Solution and Explanation

Was this answer helpful?

Questions Asked in TS EAMCET exam

If $\omega \neq 1$ is a cube root of unity, then one root among the $7^{th}$ roots of $(1+\omega)$ is

TS EAMCET - 2025
Complex numbers

View Solution

If $A = \begin{pmatrix} 1 & 2 & 3 \\ 2 & 1 & 1 \\ 1 & 3 & 1 \end{pmatrix}$ and $B = \begin{pmatrix} 2 & 3 & 4 \\ 3 & 2 & 2 \\ 2 & 4 & 2 \end{pmatrix}$, then $\sqrt{|\text{Adj}(AB)|} =$

TS EAMCET - 2025
Matrices and Determinants

View Solution

If $ p_1, p_2, p_3 $ are the altitudes and $ a=4, b=5, c=6 $ are the sides of a triangle ABC, then $ \frac{1}{p_1^2} + \frac{1}{p_2^2} + \frac{1}{p_3^2} = $

TS EAMCET - 2025
Geometry

View Solution

If $\cos\alpha = \frac{l\cos\beta+m}{l+m\cos\beta}$, then $\frac{\tan^2(\alpha/2)}{\tan^2(\beta/2)} =$

TS EAMCET - 2025
Trigonometry

View Solution

\( (\frac{1+i}{1-i})^{228}\)

Show Hint

The Correct Option is C

Solution and Explanation

Top Questions on Algebra

Questions Asked in TS EAMCET exam