Question:medium

Formal charge on sulphur atom in the following three Lewis structures I, II and III respectively is \[ \text{I.}\quad \ddot{S}=C=\ddot{N} \] \[ \text{II.}\quad :S-C\equiv N: \] \[ \text{III.}\quad :S\equiv C-N: \]

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Use \[ \text{Formal Charge} = \text{Valence Electrons} - \text{Lone Pair Electrons} - \frac{\text{Bonding Electrons}}{2}. \] For sulphur: \[ V=6. \] More bonds generally make the formal charge more positive, while more lone pairs make it more negative.
Updated On: Jul 29, 2026
  • \(0,+1,-1\)
  • \(+1,0,-1\)
  • \(0,-1,+1\)
  • \(+1,-1,0\)
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The Correct Option is C

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