Question:medium

Force F depends on distance \(x\) and time \(t\) as \(F = ax^ 2 + bt\;\frac{1}{2}\) . Final dimension of \(\frac{b^2}{a}\) is

Updated On: Mar 27, 2026
  • \(M^{ - 1} L^2 T^{-3}\)
  • \(M ^1 L^{ -3} T^3\)
  • \(M^ 1 L^3 T^{-3}\)
  • \(M ^2 L^ 2 T^1\)
Show Solution

The Correct Option is C

Solution and Explanation

Option (C): \(M^ 1 L^3 T^{-3}\)

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