Question:medium

for $|x| < 1$, sin(tan-1x) equal to

Show Hint

Drawing a right-angled triangle is a very effective and quick method for simplifying expressions involving compositions of trigonometric and inverse trigonometric functions. Always label the sides based on the given inverse function and then use Pythagoras' theorem to find the third side.
Updated On: Apr 2, 2026
  • $\frac{1}{\sqrt{1+x^2}}$
  • $\frac{1}{\sqrt{1-x^2}}$
  • $\frac{x}{\sqrt{1-x^2}}$
  • $\frac{x}{\sqrt{1+x^2}}$
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Concept Identification: This problem requires evaluating a trigonometric function of an inverse trigonometric function. A common approach involves constructing a right-angled triangle to represent the inverse trigonometric function and then deriving the required trigonometric ratio.

Step 2: Method Outline: Let \(\theta = \tan^{-1}x\), which means \(\tan\theta = x\). The objective is to determine \(\sin\theta\). This relationship can be visualized using a right-angled triangle.

Step 3: Derivation: Given \(\theta = \tan^{-1}x\), we have \(\tan\theta = x\). This can be expressed as \(\frac{x}{1}\). In a right-angled triangle, \(\tan\theta = \frac{\text{Opposite}}{\text{Adjacent}}\). Assigning the side opposite to \(\theta\) as \(x\) and the adjacent side as 1, the hypotenuse can be calculated using the Pythagorean theorem:
\[ \text{Hypotenuse}^2 = x^2 + 1^2 = 1 + x^2 \]
\[ \text{Hypotenuse} = \sqrt{1 + x^2} \]
To find \(\sin(\tan^{-1}x)\), which is \(\sin\theta\), we use the formula \(\sin\theta = \frac{\text{Opposite}}{\text{Hypotenuse}}\).
\[ \sin\theta = \frac{x}{\sqrt{1+x^2}} \]

Step 4: Conclusion: Consequently, \(\sin(\tan^{-1}x) = \frac{x}{\sqrt{1+x^2}}\).
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