Question:medium
For two real numbers \(a,b\) define
\[
a \perp b = a+b+ab,\quad a \square b = a^2+b^2,\quad a \odot b = 3a+2b
\]
then
\[
[(7 \square 5)\odot 6]\perp 8=
\]
For two real numbers \(a,b\) define
\[
a \perp b = a+b+ab,\quad a \square b = a^2+b^2,\quad a \odot b = 3a+2b
\]
then
\[
[(7 \square 5)\odot 6]\perp 8=
\]
Show Hint
In custom operation questions, solve strictly from innermost brackets outward using the given definitions.
Updated On: Jul 15, 2026
- \(19360\)
- \(7900\)
- \(2222\)
- \(2114\)
Show Solution
The Correct Option is D
Solution and Explanation
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