Question

For two matrices \(A\) and \(B\), given that \( A^{-1} = \frac{1}{8}B \) then inverse of \( (8A) \) is

• A. \( \frac{1}{8}B \)
• B. \( 8B \)
• C. \( \frac{1}{64}B \)
• D. \( B \)

Hint:

Always remember: \( (kA)^{-1} = \frac{1}{k}A^{-1} \). Substitute carefully when \(A^{-1}\) is already given.

Answer 1

The Correct Option is C