The given reaction is:
\(N_2(g) + 3H_2(g) ⇋ 2NH_3(g) + \text {Heat}\)
This is an exothermic reaction meaning that heat is released when forming ammonia. Let's analyze the factors affecting this equilibrium:
The equilibrium shifts in the forward direction (formation of ammonia) when the pressure is increased and the temperature is decreased, which corresponds to option 3.
At a given temperature and pressure, the equilibrium constant values for the equilibria are given below:
$ 3A_2 + B_2 \rightleftharpoons 2A_3B, \, K_1 $
$ A_3B \rightleftharpoons \frac{3}{2}A_2 + \frac{1}{2}B_2, \, K_2 $
The relation between $ K_1 $ and $ K_2 $ is: