Question:medium
For the homogeneous equilibrium \(N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)}\), the equilibrium constants \(K_P\) and \(K_C\) are related as:
For the homogeneous equilibrium \(N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)}\), the equilibrium constants \(K_P\) and \(K_C\) are related as:
Show Hint
Always count gaseous coefficients only to find $\Delta n_g$.
Updated On: Apr 27, 2026
- $K_{P}=K_{C}(RT)^{2}$
- $K_{P}=K_{C}(RT)^{-2}$
- $K_{P}=K_{C}(RT)^{-3}$
- $K_{P}=K_{C}(RT)^{3}$
- $K_{P}=K_{C}(RT)$
Show Solution
The Correct Option is B
Solution and Explanation
Was this answer helpful?
0
Top Questions on Law Of Chemical Equilibrium And Equilibrium Constant
- For the reaction \( \mathrm{N_2} + 3\mathrm{H_2} \rightleftharpoons 2\mathrm{NH_3} \), the equilibrium constant \(K_c\) is 0.5 at a certain temperature. If initially, 1 mole of \(\mathrm{N_2}\) and 3 moles of \(\mathrm{H_2}\) are placed in a 1 L container, what is the equilibrium concentration of \(\mathrm{NH_3}\)?
- BITSAT - 2025
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- For the reaction $ N_2 + 3H_2 \rightleftharpoons 2NH_3 $, if initially 1 mole of $ N_2 $ and 3 moles of $ H_2 $ are taken and at equilibrium 0.4 moles of $ NH_3 $ are formed, find the equilibrium concentration of $ H_2 $.
- BITSAT - 2025
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- A zero-order reaction is one whose rate is independent of:
- CBSE Class XII - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
At a given temperature and pressure, the equilibrium constant values for the equilibria are given below:
$ 3A_2 + B_2 \rightleftharpoons 2A_3B, \, K_1 $
$ A_3B \rightleftharpoons \frac{3}{2}A_2 + \frac{1}{2}B_2, \, K_2 $
The relation between $ K_1 $ and $ K_2 $ is:- NEET (UG) - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- Want to practice more? Try solving extra ecology questions todayView All Questions
