Question:medium

For an ideal gas, the isothermal compressibility $k_T = -\frac{1}{V}\left(\frac{\partial V}{\partial P}\right)_T$ is _ _ _.

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For ideal gas, isothermal compressibility always equals $\frac{1}{P}$, independent of temperature and moles
Updated On: Jun 1, 2026
  • $\frac{1}{P}$
  • $\frac{1}{T}$
  • $\frac{nR}{P}$
  • $nRT$
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The Correct Option is A

Solution and Explanation

Step 1: Start from the gas law.
\[ V = \frac{nRT}{P} \]

Step 2: Differentiate at constant T.
\[ \left(\frac{\partial V}{\partial P}\right)_T = -\frac{nRT}{P^2} \]

Step 3: Put into the definition.
\[ k_T = -\frac{1}{V}\left(-\frac{nRT}{P^2}\right) = \frac{P}{nRT}\cdot\frac{nRT}{P^2} = \frac{1}{P} \]

Step 4: Answer.
\[ \boxed{\frac{1}{P}} \]
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