Question:medium

For an ellipse, distance between centre and focus is \(\sqrt7\) and semi-latus rectum is \(\frac{9}{4}\). Area of triangle formed by foci and one end of minor axis is

Show Hint

In ellipse geometry, focus–minor axis triangle area simplifies to \(cb\).
Updated On: Jun 22, 2026
  • \(\frac{\sqrt7}{4}\)
  • \(9\sqrt7\)
  • \(3\sqrt7\)
  • \(\frac{\sqrt7}{2}\) \bigskip
Show Solution

The Correct Option is C

Solution and Explanation

Was this answer helpful?
0