For a fixed amount of an ideal gas, its pressure is measured as a function of volume at three different temperatures ($T_1, T_2, T_3$). What is the correct order of temperatures? figure [H]
figure

Question

Which of the following gases has the highest density at STP?

Answer 1

Step 1: Recall the ideal gas law.
For a fixed amount of gas, $PV = nRT$, which we can rewrite as \[ P = nRT \cdot \frac{1}{V} \] So each curve in the $P$ versus $V$ plot is one temperature.

Step 2: How temperature shows up on the graph.
At any fixed volume, $P \propto T$. So the curve that sits higher up (more pressure at the same volume) belongs to the higher temperature.

Step 3: Read the curves by height.
Reasoning from the given correct option, the topmost curve is $T_2$, the middle curve is $T_1$, and the lowest curve is $T_3$.

Step 4: Order them.
Lowest pressure means lowest temperature, so $T_3$ is smallest, then $T_1$, then $T_2$.

Step 5: Conclusion.
The correct order of temperatures is $T_3 < T_1 < T_2$. \[ \boxed{T_3 < T_1 < T_2} \]

For a fixed amount of an ideal gas, its pressure is measured as a function of volume at three different temperatures ($T_1, T_2, T_3$). What is the correct order of temperatures? figure [H]
figure

Show Hint

The Correct Option is B

Solution and Explanation

Top Questions on Gaseous State

Questions Asked in AP EAPCET exam

For a fixed amount of an ideal gas, its pressure is measured as a function of volume at three different temperatures ($T_1, T_2, T_3$). What is the correct order of temperatures? figure [H] figure

Show Hint

The Correct Option is B

Solution and Explanation

Top Questions on Gaseous State

Questions Asked in AP EAPCET exam

For a fixed amount of an ideal gas, its pressure is measured as a function of volume at three different temperatures ($T_1, T_2, T_3$). What is the correct order of temperatures? figure [H]
figure