Question:medium

For a first-order reaction, the unit of rate constant is:

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Zero-order unit: \( \text{mol L}^{-1} s^{-1} \)
First-order unit: \( s^{-1} \)
Second-order unit: \( \text{L mol}^{-1} s^{-1} \)
Identifying the order from the unit of \( k \) is a common exam trick!
Updated On: Feb 9, 2026
  • mol \( L^{-1} s^{-1} \)
  • \( s^{-1} \)
  • L \( mol^{-1} s^{-1} \)
  • mol \( L^{-1} \)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Recall what a rate constant represents. 
The rate constant $k$ relates the speed of a chemical reaction to the concentrations of the reacting species.
Its dimensional units are not fixed and depend on the overall order of the reaction.

Step 2: Write the general expression for units.
For a reaction of order $n$, the units of the rate constant are given by:

\[ (\text{concentration})^{\,1-n} \times (\text{time})^{-1} \]

Since concentration is usually expressed in $\text{mol L}^{-1}$, this form can be applied directly.

Step 3: Apply the formula to a first-order reaction.
For a first-order reaction, $n = 1$.
Substituting into the general expression:

\[ (\text{mol L}^{-1})^{\,1-1} \times s^{-1} \]

\[ (\text{mol L}^{-1})^{0} \times s^{-1} = s^{-1} \]

This shows that the rate constant for a first-order reaction does not depend on concentration units.

Step 4: Final conclusion.
The unit of the rate constant for a first-order reaction is:

\[ \boxed{s^{-1}} \]

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