Question:medium

For a feasible region bounded by the corner points $(0,3)$, $(3,2)$, and $(5,0)$ in the first quadrant, the non-trivial constraints of the linear programming problem are:

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You can quickly check options by plugging in the intersection corner point $(3,2)$. For option (A): $3+2=5 \le 5$ (True) and $3+3(2)=9 \le 9$ (True).
  • $x + y \le 5, \ x + 3y \le 9$
  • $x + y \le 5, \ x + 3y \ge 9$
  • $x + y \ge 5, \ x + 3y \le 9$
  • $x + y \ge 5, \ 3x + y \le 9$
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The Correct Option is A

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