Question:medium

For a common emitter configuration, if '$\alpha$' and '$\beta$' have their usual meanings, the incorrect relation between '$\alpha$' and '$\beta$' is

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Physics Tip: Because the collector current is always slightly less than the emitter current, $\alpha$ is always slightly less than 1, whereas $\beta$ is usually much larger than 1.
Updated On: Apr 23, 2026
  • $\frac{1}{\alpha} = \frac{1}{\beta} + 1$
  • $\alpha = \frac{\beta}{1 - \beta}$
  • $\alpha = \frac{\beta}{1 + \beta}$
  • $\frac{1}{\beta} = \frac{1}{\alpha} - 1$
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The Correct Option is B

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