Question

Follwoing compounds are given : (a)${CH3CH2OH }$ (b)${ CH3COCH3}$ (c)$CH_3- \underset{\overset{|}{C}H_3}{C}HOH$ (d)${CH3OH }$ Which of the above compounds(s), on being warmed with iodine solution and $NaOH$, will give iodoform ?

• A. Only (b)
• B. (a), (b) and (c)
• C. (a) and (b)
• D. (a), (c) and (d)

Answer 1

The Correct Option is B

To determine which of the given compounds will give iodoform on being warmed with iodine solution and $NaOH$, we need to identify the compounds capable of undergoing the iodoform reaction. The iodoform test is typically given by compounds that have a methyl ketone group ($CH_3C=O$) or alcohols that can be oxidized to form a methyl ketone.

• (a) ${CH3CH2OH}$ (Ethanol): This compound can be oxidized by iodine in the presence of base to form acetaldehyde ($CH_3CHO$), which then gives a positive iodoform test.
• (b) ${CH3COCH3}$ (Acetone): This compound is a methyl ketone and directly gives a positive iodoform test.
• (c) $CH_3- \underset{\overset{|}{C}H_3}{C}HOH$ (2-Propanol): This secondary alcohol is oxidized to form acetone, which then as a methyl ketone gives a positive iodoform test.
• (d) ${CH3OH}$ (Methanol): This compound does not have the required structure to undergo the iodoform reaction.

Therefore, compounds (a), (b), and (c) will give iodoform when warmed with iodine solution and $NaOH$. The correct answer is thus:

Correct Answer: (a), (b) and (c)