Question:medium

Fluorine reacts with ice and results in the change:
\(H_2O(s) + F_2{(g)} \rightarrow HF{(g)} + HOF{(g)}\) Justify that this reaction is a redox reaction.

Updated On: Jan 19, 2026
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Solution and Explanation

Given reaction:

H2O(s) + F2(g) → HF(g) + HOF(g)


Justification that the reaction is a redox reaction:

To justify whether a reaction is a redox reaction, we examine the changes in oxidation states of the elements involved.


Oxidation states of elements:

Before reaction:

  • In H2O: Hydrogen = +1, Oxygen = −2
  • In F2: Fluorine = 0 (elemental state)

After reaction:

  • In HF: Hydrogen = +1, Fluorine = −1
  • In HOF: Hydrogen = +1, Oxygen = 0, Fluorine = −1

Changes in oxidation states:

  • Fluorine changes from 0 in F2 to −1 in HF and HOF. This shows reduction.
  • Oxygen changes from −2 in H2O to 0 in HOF. This shows oxidation.

Conclusion:

Since fluorine undergoes reduction and oxygen undergoes oxidation simultaneously, the reaction involves both oxidation and reduction.

Therefore, the given reaction is a redox reaction.

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