Find the mean and variance for the following frequency distribution.
| Classes | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| Frequencies | 5 | 8 | 15 | 16 | 6 |
| Class | Frequency \(f_i\) | \(mid-point\,x_i\) | \(y_i=\frac{x_i-25}{10}\) | \(y_i^2\) | \(f_iy_i\) | \(f_iy_1^2\) |
| 0-10 | 5 | 5 | -2 | 4 | -10 | 20 |
| 10-20 | 8 | 15 | -1 | 1 | -8 | 8 |
| 20-30 | 15 | 25 | 0 | 0 | 0 | 0 |
| 30-40 | 16 | 35 | 1 | 1 | 16 | 16 |
| 40-50 | 6 | 45 | 2 | 12 | 12 | 24 |
| 50 | 10 | 68 |
Mean, \(\bar{x}=A\frac{\sum_{i=1}^5f_ix_i}{n}×h=25+\frac{10}{50}×10=25+2=27\)
Variance (σ2) = \(\frac{h^2}{N^2}[N\sum_{i=1}^5f_iy_i^2-(\sum_{i=1}^5f_iy_i)^2]\)
\(=\frac{(10)^2}{(50)^2}[50×68-(10)^2]\)
\(\frac{1}{25}[3400-100]=\frac{3300}{25}\)
\(=132\)
If the mean and the variance of 6, 4, a, 8, b, 12, 10, 13 are 9 and 9.25 respectively, then \(a + b + ab\) is equal to: