Question:medium

Find the mean and variance for the following frequency distribution.

Classes0-1010-2020-3030-4040-50
Frequencies5815166

Updated On: Jan 22, 2026
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Solution and Explanation

ClassFrequency \(f_i\)\(mid-point\,x_i\)\(y_i=\frac{x_i-25}{10}\)\(y_i^2\)\(f_iy_i\)\(f_iy_1^2\)
0-1055-24-1020
10-20815-11-88
20-3015250000
30-401635111616
40-506452121224
 50   1068

Mean,  \(\bar{x}=A\frac{\sum_{i=1}^5f_ix_i}{n}×h=25+\frac{10}{50}×10=25+2=27\) 

Variance (σ2) = \(\frac{h^2}{N^2}[N\sum_{i=1}^5f_iy_i^2-(\sum_{i=1}^5f_iy_i)^2]\)

\(=\frac{(10)^2}{(50)^2}[50×68-(10)^2]\)

\(\frac{1}{25}[3400-100]=\frac{3300}{25}\)

\(=132\)

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