Question:medium
Find the equation of chord of the circle x²+y²=8x bisected at the point (4,3).
Find the equation of chord of the circle x²+y²=8x bisected at the point (4,3).
Show Hint
Chord bisector passes through midpoint perpendicular to radius.
Updated On: Mar 18, 2026
- y=3
- y=1
- y=6
- y=7
Show Solution
The Correct Option is A
Solution and Explanation
Was this answer helpful?
0
Top Questions on Circles
- In the given figure, O is the centre of the circle. PQ and PR are tangents. Show that the quadrilateral PQOR is cyclic.
- In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :
- In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle OAB = 15^\circ \), then \( \angle APB \) equals :
- PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.
- Want to practice more? Try solving extra ecology questions todayView All Questions