Let:
The smaller odd positive integer be x.
Since the numbers are consecutive odd integers,
the next integer is x + 2.
Given that both integers are smaller than 10,
x + 2 < 10
Condition: Sum is more than 11
x + (x + 2) > 11
2x + 2 > 11
2x > 9
x > 4.5
Possible values of x:
x is an odd positive integer such that
5 < x ≤ 7
So,
x = 5, 7
Corresponding pairs:
(5, 7) → sum = 12
(7, 9) → sum = 16
Final Answer:
The required pairs of consecutive odd positive integers are:
(5, 7) and (7, 9)