Question:medium

Figure shows two semicircular loops of radii $R_1$ and $R_2$ carrying current $I$. The magnetic field at the common centre '$O$' is

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The magnetic field at the center of a circular loop is $B = \frac{\mu_0 I}{2R}$. For a semicircle, it is exactly half of that, i.e., $B = \frac{\mu_0 I}{4R}$.
Updated On: Apr 28, 2026
  • \frac{\mu_0 I}{4} (\frac{1}{R_1} + \frac{1}{R_2})
  • \frac{\mu_0 I}{4} (\frac{1}{R_1} - \frac{1}{R_2})
  • \frac{\mu_0 I}{2\pi} (\frac{1}{R_1} + \frac{1}{R_2})
  • \frac{\mu_0 I}{2\pi} (\frac{1}{R_1} - \frac{1}{R_2})
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The Correct Option is A

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