Question:medium
\( \mathrm{Fe_2O_{3(s)} + 3H_{2(g)} \rightarrow 2Fe_{(s)} + 3H_2O_{(l)}} \) \(\text{(Given: } \Delta H^\circ(\mathrm{H_2O_{(l)}}) = -285.83\,\text{kJ mol}^{-1},\ \Delta H^\circ(\mathrm{Fe_2O_{3(s)}}) = -824.2\,\text{kJ mol}^{-1}\text{)}\)
\( \mathrm{Fe_2O_{3(s)} + 3H_{2(g)} \rightarrow 2Fe_{(s)} + 3H_2O_{(l)}} \) \(\text{(Given: } \Delta H^\circ(\mathrm{H_2O_{(l)}}) = -285.83\,\text{kJ mol}^{-1},\ \Delta H^\circ(\mathrm{Fe_2O_{3(s)}}) = -824.2\,\text{kJ mol}^{-1}\text{)}\)
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Always remember: elements in their standard states have \(\Delta_f H^\circ = 0\).
Updated On: Apr 27, 2026
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The Correct Option is A
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