Given:
( x/3 + 1/x )5
Step 1: Apply Binomial Theorem
(a + b)5 = a5 + 5a4b + 10a3b2 + 10a2b3 + 5ab4 + b5
Let
a = x/3, b = 1/x
Step 2: Evaluate each term
a5 = x5/243
5a4b = 5x3/81
10a3b2 = 10x/27
10a2b3 = 10/(9x)
5ab4 = 5/(3x3)
b5 = 1/x5
Step 3: Write the expansion
(x/3 + 1/x)5 =
x5/243 + 5x3/81 + 10x/27 + 10/(9x) + 5/(3x3) + 1/x5
Final Answer:
(x/3 + 1/x)5 = x5/243 + 5x3/81 + 10x/27 + 10/(9x) + 5/(3x3) + 1/x5