Given:
(2/x − x/2)5
Step 1: Apply Binomial Theorem
(a − b)5 = a5 − 5a4b + 10a3b2 − 10a2b3 + 5ab4 − b5
Let
a = 2/x, b = x/2
Step 2: Evaluate each term
a5 = 32/x5
5a4b = 40/x3
10a3b2 = 20/x
10a2b3 = 5x
5ab4 = 5x3/8
b5 = x5/32
Step 3: Write the expansion
(2/x − x/2)5 =
32/x5 − 40/x3 + 20/x − 5x + 5x3/8 − x5/32
Final Answer:
(2/x − x/2)5 = 32/x5 − 40/x3 + 20/x − 5x + 5x3/8 − x5/32