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Evaluate $\int \frac{1}{(x+1)\sqrt{x^2 - 1}}$ dx

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Evaluate $\int\frac1(x+1)\sqrtx-1dx$

Updated On: Apr 15, 2026

$\sqrt{\frac{x+1}{x-1}}+c$
$\sqrt{\frac{x-1}{x+1}}+c$
$\sqrt{\frac{1}{x+1}}+c$
None of these

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The Correct Option is B

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Evaluate \(\int \frac{1}{(x+1)\sqrt{x^2 - 1}}\) dx

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The Correct Option is B

Solution and Explanation

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