Question:medium

Escape velocity from earth's surface is 11 km/s. If the radius of a planet is double that of earth and the density is the same as that of earth, then the escape velocity from this planet will be:

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Escape velocity depends on both the mass and the radius of a planet. When the radius is doubled and the density remains constant, the escape velocity increases by a factor of \( \sqrt{2} \).
Updated On: Apr 22, 2026
  • 5.5 km/s
  • 11 km/s
  • 16.5 km/s
  • 22 km/s
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The Correct Option is D

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