Question:medium

Escape velocity at surface of earth is \(11.2\ \text{km/s}\). Escape velocity from a planet whose mass is the same as that of earth and radius \(1/4\) that of earth, is

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\(v_e \propto \frac{1}{\sqrt{R}}\) when \(M\) is constant.
Updated On: Apr 23, 2026
  • \(2.8\ \text{km/s}\)
  • \(15.6\ \text{km/s}\)
  • \(22.4\ \text{km/s}\)
  • \(44.8\ \text{km/s}\)
Show Solution

The Correct Option is C

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