Question:medium
Equilibrium constants are given for the following two equilibria:
\[
(i)\; A_2(g) + B_2(g) \rightleftharpoons 2AB(g); \quad K_1 = 2 \times 10^{-4}
\]
\[
(ii)\; 2AB(g) + C_2(g) \rightleftharpoons 2ABC(g); \quad K_2 = 2 \times 10^{-2}\, L\, mol^{-1}
\]
Calculate the equilibrium constant for:
\[
ABC(g) \rightleftharpoons \frac{1}{2}A_2(g) + \frac{1}{2}B_2(g) + \frac{1}{2}C_2(g)
\]
Equilibrium constants are given for the following two equilibria:
\[
(i)\; A_2(g) + B_2(g) \rightleftharpoons 2AB(g); \quad K_1 = 2 \times 10^{-4}
\]
\[
(ii)\; 2AB(g) + C_2(g) \rightleftharpoons 2ABC(g); \quad K_2 = 2 \times 10^{-2}\, L\, mol^{-1}
\]
Calculate the equilibrium constant for:
\[
ABC(g) \rightleftharpoons \frac{1}{2}A_2(g) + \frac{1}{2}B_2(g) + \frac{1}{2}C_2(g)
\]
Show Hint
Always track three transformations: reversing (reciprocal), multiplying (power), and adding (product of constants).
Updated On: May 8, 2026
- $500$ mol$^{1/2}$ L$^{1/2}$
- $4 \times 10^{-6}$ mol$^{1/2}$ L$^{1/2}$
- $500$ mol$^{-1/2}$ L$^{1/2}$
- $200$ mol$^{1/2}$ L$^{-1/2}$
- $500$ mol$^{1/2}$ L$^{-1/2}$
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At a given temperature and pressure, the equilibrium constant values for the equilibria are given below:
$ 3A_2 + B_2 \rightleftharpoons 2A_3B, \, K_1 $
$ A_3B \rightleftharpoons \frac{3}{2}A_2 + \frac{1}{2}B_2, \, K_2 $
The relation between $ K_1 $ and $ K_2 $ is:- NEET (UG) - 2024
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